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Find the value of a so that the points (1,4),(2,7),(3,a) are collinear. |
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Answer» SOLUTION :As the point (1,4),(2,7),(3,a) are COLLINEAR we have the area of the TRIANGLE with vertices (1,4),(2,7),(3,a) is zero. `THEREFORE` `1/2{1(7-a)+2(a-4)+3(4-7)}=0` or, 7-a+2a-8+12-21=0. `implies` a=10. |
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