1.

Find the value of a so that the points (1,4),(2,7),(3,a) are collinear.

Answer»

SOLUTION :As the point (1,4),(2,7),(3,a) are COLLINEAR we have the area of the TRIANGLE with vertices (1,4),(2,7),(3,a) is zero.
`THEREFORE` `1/2{1(7-a)+2(a-4)+3(4-7)}=0`
or, 7-a+2a-8+12-21=0.
`implies` a=10.


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