Find the value of discriminant.i. x2 + 7x – 1 = 0ii. 2y2 – 5y + 10

1.	Find the value of discriminant.i. x2 + 7x – 1 = 0ii. 2y2 – 5y + 10 = 0iii. √2 x2 + 4x + 2√2 = 0
Answer» i. x² +7x – 1 = 0 Comparing the above equation with ax² + bx + c = 0, we get a = 1, b = 7, c = -1 ∴ b² – 4ac = (7)² – 4 × 1 × (-1) = 49 + 4 ∴ b² – 4ac = 53 ii. 2y² – 5y + 10 = 0 Comparing the above equation with ay² + by + c = 0, we get a = 2, b = -5, c = 10 ∴ b² – 4ac = (-5)² -4 × 2 × 10 = 25 – 80 ∴ b² – 4ac = -55 iii. √2 x² + 4x + 2√2 = 0 Comparing the above equation with ax + bx + c = 0, we get a = √2, b = 4, c = 2√2 ∴ b² – 4ac = (4)² – 4 × √2 × 2√2 = 16 – 16 ∴ b² – 4ac = 0

Find the value of discriminant.i. x2 + 7x – 1 = 0ii. 2y2 – 5y + 10 = 0iii. √2 x2 + 4x + 2√2 = 0

Answer»

i. x² +7x – 1 = 0

Comparing the above equation with

ax² + bx + c = 0, we get

a = 1, b = 7, c = -1

∴ b² – 4ac = (7)² – 4 × 1 × (-1)

= 49 + 4

∴ b² – 4ac = 53

ii. 2y² – 5y + 10 = 0

Comparing the above equation with

ay² + by + c = 0, we get

a = 2, b = -5, c = 10

∴ b² – 4ac = (-5)² -4 × 2 × 10

= 25 – 80

∴ b² – 4ac = -55

iii. √2 x² + 4x + 2√2 = 0

Comparing the above equation with

ax + bx + c = 0, we get

a = √2, b = 4, c = 2√2

∴ b² – 4ac = (4)² – 4 × √2 × 2√2

= 16 – 16

∴ b² – 4ac = 0