Find the value of f (x)=3x^3-4x^2+7x+5 when x=3 and x=-3

1.	Find the value of f (x)=3x^3-4x^2+7x+5 when x=3 and x=-3
Answer» p(x) = 3x3 - 4x2 + 7x - 5Remainder when x = 3 divides p(x) is\xa0p(3) = 3 33 - 4 32 + 7 3 - 5= 3 27 - 4 9 + 21 - 5 = 61Remainder when x = - 3 divides p(x) is p(-3) = 3 (-3)3 - 4(-3)2 + 7 (-3) - 5= 3 (-27) - 4 9 - 21 - 5= -143Therefore, the required remainders are 61 and -143.

Discussion