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Find the value of K_(c) for each of the following equilibria from the value of K_(p) (a) 2 NOCl (g) hArr 2 NO(g) + Cl_(2) (g) , K_(P) = 1.8 xx 10^(-2) atm at 500 K (b) CaCO_(3) (s) hArr CaO(s) + CO_(2) (g) , K_(P) = 167 atm at 1073 K |
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Answer» Solution :(a) `2 NOCl (g) hArr 2 NO (g) + Cl_(2)` `K_(p) = 1.8 xx 10^(-2)` atm `Delta n_(g) = 3 - 2 = 1 , R = 0.0821` litre `atm K^(-1) mol^(-1) , T = 500` K `therefore "" K_(C) = (K_(P))/((RT)^(Delta n_(g))) = ((1.8 xx 10^(-2) atm))/((0.0821 L atm K^(-1) mol^(-1) xx 500 K)^(1))` `= 4.4 xx 10^(-4) mol L^(-1)` (b) ` CaCO_(3) (g) hArr CaO (s) + CO_(2) (g)` `K_(p) = 167` atm , `Delta n_g = 1` `R = 0.0821` litre and atm `K^(-1) mol^(-1) , T = 1073` K `K_(C) = (K_(P))/((RT)^(Deltan_(g))) = ((1.8 xx 10^(-2) "atm"))/((0.0821 L atm K^(-1) mol^(-1) xx 1073 K)^(1))` `1.9 mol L^(-1)` |
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