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Find the value of k if \(\mathop {\lim }\limits_{x \to 0} \frac{{-{3x^2} - 7x + 8}}{{{7x^2} + 2x + 2}} = k\) ?1. 4/32. - 3/23. Limit does not exist4. 4 |
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Answer» Correct Answer - Option 4 : 4 CONCEPT: If \(\mathop {\lim }\limits_{x \to a} f\left( x \right)\) does not result into indeterminate form, then we use direct substitution in order to find the limits. The are 7 indeterminate forms which are as follows:
CALCULATION: Given: \(\mathop {\lim }\limits_{x \to 0} \frac{{-{3x^2} - 7x + 8}}{{{7x^2} + 2x + 2}} = k\) As we know that, if \(\mathop {\lim }\limits_{x \to a} f\left( x \right)\)does not result into indeterminate form, then we use direct substitution in order to find the limits. Here, also we can see that \(\mathop {\lim }\limits_{x \to 0} \frac{{-{3x^2} - 7x + 8}}{{{7x^2} + 2x + 2}}\)does not result into any indeterminate form So, we can substitute x = 0 in the expression \(\frac{{-{3x^2} - 7x + 8}}{{{7x^2} + 2x + 2}}\) in order to find the value of k ⇒ \(\mathop {\lim }\limits_{x \to 0} \frac{{-{3x^2} - 7x + 8}}{{{7x^2} + 2x + 2}} = 4 = k\) Hence, Option D is the correct answer. |
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