1.

Find the value of k if the expressions p(x) = kx3 + 4x2 + 3x – 4 and q(x) = x3 – 4x + k leave the same remainder when divided by (x – 3) A) k = -1 B) k = 4 C) k = 3 D) k = -2

Answer»

Correct option is (A) k = -1

p(3) = q(3)

\(\Rightarrow\) 27k+36+9-4 = 27 - 12 + k

\(\Rightarrow\) 26k + 41 - 15 = 0

\(\Rightarrow\) 26k = 15 - 41 = -26

\(\Rightarrow\) k = \(\frac{-26}{26}\) = -1

Correct option is A) k = -1



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