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Find the value of k if the expressions p(x) = kx3 + 4x2 + 3x – 4 and q(x) = x3 – 4x + k leave the same remainder when divided by (x – 3) A) k = -1 B) k = 4 C) k = 3 D) k = -2 |
Answer» Correct option is (A) k = -1 p(3) = q(3) \(\Rightarrow\) 27k+36+9-4 = 27 - 12 + k \(\Rightarrow\) 26k + 41 - 15 = 0 \(\Rightarrow\) 26k = 15 - 41 = -26 \(\Rightarrow\) k = \(\frac{-26}{26}\) = -1 Correct option is A) k = -1 |
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