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Find the value of k, if `(x-3)` is a factor of `k^3x^3-x^2+3x-1`. |
Answer» Here, `f(x) = k^3x^3-x^2+3x-1` As, `(x-3)` is a factor of `k^3x^3-x^2+3x-1`, `:. f(3)` will be `0`. `:. k^3(3)^3-(3)^2+3(3) - 1 = 0` `=>27k^3 = 1` `=> k = (1/27)^(1/3) = 1/3` `=> k = 1/3`, is the required value of `k`. |
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