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Find the value of k, if (x – 3) is a factor of polynomial x3 – 9x2 + 26x + k. |
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Answer» Let p(x) = x3 – 9x2 + 26x + k By factor theorem, (x – 3) is a factor of p(x), if p(3) = 0 p(3) = 0 33 – 9(3)2 + 26(3) + k = 0 27 – 81 + 78 + k = 0 k = -24 To find the zero of x - 3: Put x - 3 = 0 We get x = 3 |
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