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Find the value of `k`, so that the equation `2x^2+kx-5=0` and `x^2-3x-4=0` may have one root in common.A. `-3`B. `-1`C. `-(27)/(4)`D. `(27)/(4)` |
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Answer» Correct Answer - A::C The value of `K` …………. `x^(2)-3x-4=0` `(x-4) (x+1) = 0` `x = -1, 4` when `x = -1` `2.1 - k - 5 = 0` `k = -3` when `x =4` `32+4k- 5 =0` `k = -27//4` |
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