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Find the value of 'k' so that the quadratic equation 3x2 - 5x - 2k = 0 has real and equal roots. |
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Answer» The given quadric equation is 3x2 - 5x - 2k = 0, and roots are real and equal Then find the value of k. Here, a = 3, b = -5 and c = -2k As we know that D = b2 - 4ac Putting the value of a = 3, b = -5 and c = -2k = (-5)2 - 4 x (3) x (- 2k) = 25 + 24k The given equation will have real and equal roots, if D = 0 Thus, 25 + 24k = 0 24k = -25 k = -25/24 Therefore, the value of k = -25/24. |
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