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Find the value of `lambda`so that the following lines are perpendicular to each other.`(x-5)/(5lambda+2)=(2-y)/5=(1-z)/(-1), x/1=(2y+1)/(4lambda)=(1-z)/(-3)`

Answer» `(x-5)/(5lambda+2)=(y-2)/-5=(z-1)/1` &
`x/1=(y+1/2)/(2lambda)=(z-1)/3`
are perpendicular to each other,So, `(5lambda+2)*1+(2lambda)(-5)+3=0`Hence, `lambda=1`


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