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Find the value of\log \left(\frac{225}{32}\right)-\log \left(\frac{25}{81}\right)+\log \left(\frac{64}{729}\right) |
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Answer» log225-log32-log25+log81+log64-log729 = log25 + log9 - log32 - log25 + 2log9 + log32 + log2 - 6log3 = 3log9 + log2 - 3log9 = log2 |
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