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Find the value of "^nC_(r-1)//"^nC_r |
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Answer» SOLUTION :`"^nC_(R-1)//^nC_r = N!//(r-1)!(n-r+1)!//n!//r!(n-r)!` `r!(n-r)!//(r-1)!(n-r+1)!` = `r!(r-1)!(n-r)!//(r-1)!(n-r+1)(n-r)!` `r/n-r+1` |
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