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Find the value of p. for which one root of the quadratic equationpr-14x + 8 = 0 is 6 times the other. |
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Answer» Given px^2-14x+8=0let a and b be the roots of the equationb=6asum of roots = -b/aproduct of roots = c/ahere a=p , b=-14 , c=8a+b=14/pab=8/p a+6a=14/p7a=14/pa=2/p a*6a=8/p6a^2=8/p3a^2=4/p 3*(2/p)^2=4/p 3*4/p^2=4/p p=3 |
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