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Find the value of p so that the lines 1−x3=7y−142p=z−32 and 7−7x3p=y−51=6−z5 are at right angles |
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Answer» Find the value of p so that the lines 1−x3=7y−142p=z−32 and 7−7x3p=y−51=6−z5 are at right angles |
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