Find the value of p,so that the lines l1:1−x3=7y−14p=z−32 and l2 – InterviewSolution

1.	Find the value of p,so that the lines l1:1−x3=7y−14p=z−32 and l2:7−7x3p=y−51=6−z5 are perpendicular to each other. Also find the equations of a line passing through a point (3,2,−4) and parallel to line l1.
Answer» Find the value of p,so that the lines $l_{1} : \frac{1 - x}{3} = \frac{7 y - 14}{p} = \frac{z - 3}{2} a n d l_{2} : \frac{7 - 7 x}{3 p} = \frac{y - 5}{1} = \frac{6 - z}{5}$ are perpendicular to each other. Also find the equations of a line passing through a point $(3, 2, - 4)$ and parallel to line $l_{1}$ .

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