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Find the value of p so that the quadratic equation px(r-3)+9 0 has twoequal roots. |
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Answer» px^2-3px+9=0 a=p , b=-3p , c=9 b^2-4ac= (-3p)^2-4(p)(9) =9p^2-36p having equal roots b^2-4ac = 9p^2-36p = 0 9p^2-36p = 0 9p(p-4) = 0 9p=0 (or) p-4=0 since, p=4 |
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