1.

Find the value of p so that the quadratic equation px(r-3)+9 0 has twoequal roots.

Answer»

px^2-3px+9=0

a=p , b=-3p , c=9

b^2-4ac= (-3p)^2-4(p)(9)

=9p^2-36p

having equal roots

b^2-4ac = 9p^2-36p = 0

9p^2-36p = 0

9p(p-4) = 0

9p=0 (or) p-4=0

since, p=4



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