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Find the value of \(tan^{-1}(tan\frac{9\pi}{8})\) |
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Answer» Given tan-1 (tan 9π/8) = tan-1 [tan (π + π/8)] = tan-1 (tan π/8) = π/8 ∴ tan-1 (tan 9π/8) = π/8 |
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