1.

Find the value of \(tan^{-1}(tan\frac{9\pi}{8})\)

Answer»

Given tan-1 (tan 9π/8) 

= tan-1 [tan (π + π/8)] 

= tan-1 (tan π/8) 

= π/8 

∴ tan-1 (tan 9π/8) = π/8



Discussion

No Comment Found