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Find the value of the currents I1, I2 and I3 flowing clockwise in the first, second and third mesh respectively.(a) 1.54A, -0.189A, -1.195A(b) 2.34A, -3.53A, -2.23A(c) 4.33A, 0.55A, 6.02A(d) -1.18A, -1.17A, -1.16AI had been asked this question during a job interview.I would like to ask this question from Mesh Analysis topic in portion Network Theorems of Basic Electrical Engineering

Answer»

The correct OPTION is (a) 1.54A, -0.189A, -1.195A

The explanation is: The three MESH equations are:

-3I1+2I2-5=0

2I1-9I2+4I3=0

4I2-9I3-10=0

Solving the equations, we get I1= 1.54A, I2=-0.189 and I3= -1.195A.



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