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Find the value of the following expressions at a = 1 and b = –2:(i) a2 + b2 + 3ab (ii) a3 + a2b + ab2 + b3 |
Answer» (i) Value of a2 + b2 + 3ab at a = 1 and b = – 2 = (1)2 + (–2)2 + 3 (1)(–2) = 1 + 4 – 6 = 5 – 6 = – 1 (ii) Value of a3 + a2b + ab2 + b3 at a = 1 and b = – 2 = (1)3 + (1)2(–2)+(1) (–2)2 + (–2)3 = 1 – 2 + 4 – 8 = 5 – 10 = – 5 |
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