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Find the value of the reaction H_2 (g) +I_2 (g) hArr2HI(g) at an instant where concentration of H_2I_2 and 'HI are found to be 0.2 mol L^(-1), 0.2 mol L^(-1), and 0.6 mol L^(-1) respectively. |
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Answer» 48 solution : ` q= ([ HI]^2)/([H_2] [I_2]) = ( 0.6 XX 0.6 )/( 0.2 xx 0.2)=9` |
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