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find the value of the sin squar 30 -3cos squar 45 -4 tan squar 60 |
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Answer» sin²30 - 3cos²45 - 4tan²60 Substituting the values, we get (1/2)² - 3((1/√2)² - 4((√3)² = 1/4 - 3/2 - 12 = 1-6/4 - 12 = -5/4 - 12 = -5-48/4 = -53/4 |
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