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Find the value of ‘x’ and ‘y’ in the adjacent figure. |
Answer» In ∆ACL, AC = CL So, ∆ACL is an isosceles triangle. In isosceles triangle, the angles which are opposite to equal sides are also equal. So, ∠A = ∠L = x° ∠C = 56° (Vertically opposite angle) In ∆ACL, we know ∠A + ∠C + ∠L = 180° ⇒ x + 56° + x = 180° ⇒ 2x + 56° – 56° = 180° – 56° ⇒ 2x =124° ⇒ 2x/2 = 124°/2 ∴ x = 62° Exterior angle at A = ∠C + ∠L ⇒ y = 56 + 62 ⇒ y = 118° |
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