Find the value of x for which the angles (2x – 5)° and (x – 10)�

1.	Find the value of x for which the angles (2x – 5)° and (x – 10)° are the complementary angles.
Answer» It is given that (2x – 5)° and (x – 10)° are the complementary angles. So we can write it as (2x – 5)° + (x – 10)° = 90° 2x – 5° + x – 10° = 90° On further calculation 3x – 15° = 90° So we get 3x = 105° By division x = 105/3 x = 35° Therefore, the value of x for which the angles (2x – 5)° and (x – 10)° are the complementary angles is 35°.

Find the value of x for which the angles (2x – 5)° and (x – 10)° are the complementary angles.

Answer»

It is given that (2x – 5)° and (x – 10)° are the complementary angles.

So we can write it as

(2x – 5)° + (x – 10)° = 90°

2x – 5° + x – 10° = 90°

On further calculation

3x – 15° = 90°

So we get

3x = 105°

By division

x = 105/3

x = 35°

Therefore, the value of x for which the angles (2x – 5)° and (x – 10)° are the complementary angles is 35°.