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Find the value of x, if \(\begin{bmatrix}3x\,+\,y & -y \\[0.3em]2y\,-\,x & 3 \\[0.3em]\end{bmatrix}\) = \(\begin{bmatrix}1 & 2 \\[0.3em]-5 & 3 \\[0.3em]\end{bmatrix}\) |
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Answer» Given, \(\begin{bmatrix} 3x\,+\,y & -y \\[0.3em] 2y\,-\,x & 3 \\[0.3em] \end{bmatrix} \)= \(\begin{bmatrix} 1 & 2 \\[0.3em] -5 & 3 \\[0.3em] \end{bmatrix} \) Equating the corresponding elements, we get ⇒ 3x + y = 1, -y = 2, 2y - x = -5 ⇒ y = -2 Putting it in 3x + y = 1 or 2y - x = - 5 we get 3x - 2 = 1 or - 4 - x = - 5 ⇒ x = 1 or - x = - 1 ⇒ x = 1 Hence, x = 1 and y = - 2 |
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