1.

Find the value of x, if the ratio of 10th term to 11th term of the expansion (2−3x3)20 is 45 : 22. Or Find the value of a, so that the term independent of x in (√x+ax2)10 is 405.

Answer»

Find the value of x, if the ratio of 10th term to 11th term of the expansion (23x3)20 is 45 : 22.

Or

Find the value of a, so that the term independent of x in (x+ax2)10 is 405.



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