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Find the value of ‘x’ in the following figures |
Answer» a) From the figure, ∠A = 35°, ∠B = x° and exterior angle at C = 70° Exterior angle of a triangle is equal to the sum of its opposite interior angles. Exterior angle at C = ∠A + ∠B = 70° ⇒ 35° + x= 70° ⇒ 35° + x – 35° = 70° – 35° ∴ x = 35° b) From the figure, ∠P = 4x, ∠Q = 3x and exterior angle at R = 119° Exterior angle of a triangle is equal to the sum of its opposite interior angles. Exterior angle at R = ∠P + ∠Q = 119° ⇒ 4x + 3x = 119° ⇒ 7x = 119° ⇒ 7x/7 = 119°/7 ∴ x = 17° |
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