1.

Find the value of ‘x’ in the following figures

Answer»

a)  From the figure, 

∠A = 35°, ∠B = x° and exterior angle at C = 70° 

Exterior angle of a triangle is equal to the sum of its opposite interior angles. 

Exterior angle at C = ∠A + ∠B = 70° 

⇒ 35° + x= 70° 

⇒ 35° + x – 35° 

= 70° – 35° 

∴ x = 35°

b) From the figure, ∠P = 4x, ∠Q = 3x and exterior angle at R = 119° 

Exterior angle of a triangle is equal to the sum of its opposite interior angles. 

Exterior angle at R = ∠P + ∠Q = 119° 

⇒ 4x + 3x = 119° 

⇒ 7x = 119°

⇒ 7x/7 = 119°/7

∴ x = 17°



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