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Find the value of ‘x’ in the given figure. |
Answer» In the given figure, ∠HAC = ∠TAE = a (∵ Vertically opposite angles) In ∆AHC, we know, ∠H + ∠C + ∠HAC 180° ⇒ 60° + 80° + a = 180° ⇒ 140° + a – 140° = 180°- 140° … a = 40°. ∴ ∠HAC = ∠TAE = a = 40° In ∆ATE, we know, ∠T + ∠TAE + ∠E = 180° ⇒ x + a + 70° = 180° ⇒ x + 40° + 70° = 180° ⇒ x + 110°- 110° = 180°- 110° ∴ x = 70° |
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