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Find the value of ‘x’ in the given triangles. |
Answer» In ∆CUT, ∠C = 64°, ∠U = 46° and exterior angle ∠CTE = x =? ∠C + ∠U + ∠T= 180° ⇒ 64° + 46° + ∠T = 180° ⇒ 110° + ∠T= 180° ⇒ 110° + ∠T – 110° = 180°- 110° ∠UTC = ∠T = 70° ∠UTC + ∠CTE = 180° (linear pair of angles) ⇒ 70° + x° = 180° ⇒ 70° + x° – 70° = 180°-70° ∴ x = 110° |
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