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Find the value of x so that (–2)3 × (–2)–6 = (–2)2x–1. |
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Answer» From the laws of exponents , we know that, am × an = a(m+n) So , we have , (–2)3 × (–2)–6 =(-2)(3)+(-6) = (-2)(-3) Now , we have , (-2)(-3) = (-2)(2x-1) On comparing both the sides , we get -3 = 2x-1 2x = -3 + 1 2x = -2 x = -2/2 = -1 ∴ x = -1 |
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