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Find the value of x that will give minimum values of the function 2 x3 — 11 x2+12x+10?Ans

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Ans: x=3

Let f(x) = \(2x^3 -11x^2+12x+10\)

\(df/dx\)\(6x^2-22x+12\)  And so roots of \(df/dx = 0\) are 3 and 2/3 by solving the quadratic eqn.

Check \(d^2f/dx^2 = 12x-22\) at x=3 and x=2/3. At x=3 \(d^2f/dx^2\) gives positive value and thus x=3 is a point of minima. 



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