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Find the value(s) of k, for which the equation kx2-kx + 1 = 0 has equal roots. |
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Answer» For equal roots, b2 -4ac=0 Here, a= k, b= -k and c=1 k2 - 4(k)(1)=0 i.e. k(k- 4)=0 i.e. k=0 or k= 4 rejecting k=0, we get k= 4. |
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