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Find the values `k` for which the quadratic equation `2x^2 + kx +3=0` has two real equal roots |
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Answer» The given equation is `2x^(2)+kx+3=0.` This is of the form `ax^(2)+bx+c=0,` where a=2, b=k and c=3. `:." "D=(b^(2)-4ac)=(k^(2)-4xx2xx3)=(k^(2)-24).` For real and equal roots, we much have `D=0impliesk^(2)-24=0impliesk=+-sqrt(24)impliesk=+-sqrt(24)=+-2sqrt(6).` Hence, `2sqrt(6)` and `-2sqrt(6)` are the required values of k. |
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