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Find the values of a and 6 for which x = 3/4 and x = -2 are the roots of the equation ax2 + bx – 6 = 0. |
Answer» Given equation is ax2 + bx – 6 = 0 As 3/4 is its root, then must satisfy the equation a(3/4)2 + b(3/4) – 6 = 0 9a +12b – 96 = 0 ….(1) Again, x = -2 is its root a(-2)2 + b(-2) – 6 = 0 4a – 2b – 6 = 0 …(2) Solving (1) and (2), we get a = 4 and b = 5 |
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