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Find the values of k of the following quadratic equation so that they have two equal roots.2x2 + kx + 3 = 0 |
Answer» Given : 2x2 + kx + 3 = 0 has equal roots ∴ b2 – 4ac = 0 Here a = 2; b = k; c = 3 b2 – 4ac = (k)2 – 4(2)(3) = 0 ⇒ k2 – 24 = 0 ⇒ k2 = 24 ⇒ k = √24 = ± 2√6 |
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