1.

Find the values of n in each of the following:(i) 52n × 53 = 511(ii) 9 x 3n = 37(iii) 8 x 2n+2 = 32 

Answer»

(i) Given 52n x 53 = 511

= 52n+3 = 511

On equating the coefficients, we get

2n + 3 = 11

⇒2n = 11- 3

⇒2n = 8

⇒ n = (8/2)

⇒ n = 4

(ii)  Given 9 x 3n = 37

= (3)2 x 3n = 37

= (3)2+n = 37

On equating the coefficients, we get

2 + n = 7

⇒ n = 7 – 2  

n = 5

(iii) Given 8 x 2n+2 = 32

= (2)3 x 2n+2 = (2)5      [since 23 = 8 and 25 = 32]
= (2)3+n+2 = (2)5 

On equating the coefficients, we get

3 + n + 2 = 5

⇒ n + 5 = 5

⇒ n = 5 -5

⇒ n = 0


Discussion

No Comment Found

Related InterviewSolutions