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\(\frac{1}{(216)^{\frac{-2}{3}}}+\frac{1}{(256)^\frac{-3}{4}}+\frac{1}{(243)^{\frac{-1}{5}}}\) is equal to(a) 103 (b) 105 (c) 107 (d) 101 |
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Answer» (a) 103 Given exp. = \(\frac{1}{{(6^3)}^{-\frac{2}{3}}}+\frac{1}{(4^4)^{-\frac{3}{4}}}+\frac{1}{(3^5)^{-\frac{1}{5}}}\) = \(\frac{1}{6^{-2}}+\frac{1}{4^{-3}}+\frac{1}{3^{-1}}\) = 62 + 43 + 3 = 36 + 64 + 3 = 103 |
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