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Find the values of `p`for whch the equadratic equation `(2p+1)x^2-(7p+2)x+(7p-3)=0` |
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Answer» Correct Answer - `p=4" or "p=(-4)/(7)` `D=(7p+2)^(2)-4(2p+1)(7p-3)=-7p^(2)+24p+16.` `:." "D=0implies7p^(2)-24p-16=0implies7p^(2)-28p+4p-16=0` `implies7p(p-4)+4(p-4)=0implies(p-4)(7p+4)=0.` |
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