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Find the values of p for which the quadratic equation 2x2 + px + 8 = 0 has real roots. |
Answer» 2x2 + px + 8 = 0 Compare given equation with the general form of quadratic equation, which is ax2 + bx + c = 0 a = 2, b = p, c = 8 Find D: D = b2 – 4ac = p2 – 4 x 2 x 8 = p2 – 64 Since roots are real, so D ≥ 0 p2 – 64 ≥ 0 p2 ≥ 64 ≥ (±8)2 Either p ≥ 8 or p ≤ -8 |
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