InterviewSolution
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Find the values of the following trigonometric ratios:(i) sin (-11π/6)(ii) cosec (-20π/3)(iii) tan (-13π/4)(iv) cos 19π/4(v) sin 41π/4(vi) cos 39π/4(vii) sin 151π/6 |
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Answer» (i) Given as sin (-11π/6) sin (-11π/6) = sin (-330°) = – sin (90 × 3 + 60)° Here, 330° lies in the IV quadrant in which the sine function is negative. sin (-330°) = – sin (90 × 3 + 60)° = – (-cos 60°) = – (-1/2) Thus, 1/2 (ii) Given as cosec (-20π/3) cosec (-20π/3) = cosec (-1200)° = – cosec (1200)° = – cosec (90 × 13 + 30)° Here, 1200° lies in the II quadrant in which cosec function is positive. cosec (-1200)° = – cosec (90 × 13 + 30)° = – sec 30° = -2/√3 (iii) Given as tan (-13π/4) tan (-13π/4) = tan (-585)° = – tan (90 × 6 + 45)° Here, 585° lies in the III quadrant in which the tangent function is positive. tan (-585)° = – tan (90 × 6 + 45)° = – tan 45° = -1 (iv) Given as cos 19π/4 cos 19π/4 = cos 855° = cos (90 × 9 + 45)° Here, 855° lies in the II quadrant in which the cosine function is negative. cos 855° = cos (90 × 9 + 45)° = – sin 45° = – 1/√2 (v) Given as sin 41π/4 sin 41π/4 = sin 1845° = sin (90 × 20 + 45)° Here, 1845° lies in the I quadrant in which the sine function is positive. sin 1845° = sin (90 × 20 + 45)° = sin 45° = 1/√2 (vi) Given as cos 39π/4 cos 39π/4 = cos 1755° = cos (90 × 19 + 45)° Here, 1755° lies in the IV quadrant in which the cosine function is positive. cos 1755° = cos (90 × 19 + 45)° = sin 45° = 1/√2 (vii) Given as sin 151π/6 sin 151π/6 = sin 4530° = sin (90 × 50 + 30)° Here, 4530° lies in the III quadrant in which the sine function is negative. sin 4530° = sin (90 × 50 + 30)° = – sin 30° Thus, -1/2 |
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