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If sin θ + cos θ = 1, then the value of sin 2θ is equal to A. 1 B. 1/2 C. 0 D. –1 |
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Answer» C. 0 Given that, sin θ + cos θ = 1 Squaring both sides, we get ⇒ (sin θ + cos θ)2 = 1 ⇒ sin2θ + cos2θ + 2sin θ cos θ = 1 ⇒ 1 + sin2θ = 1 ⇒ sin2θ = 1-1 = 0 |
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