InterviewSolution
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Find the vector equation of the plane passing through the intersection of the planes and through the point (2,1,3). |
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Answer» Let the planes be P1 : 2x + 2y -3z – 7 = 0, P2 : 2x +5y + 3z = 9 ∴ Required equation be P1+ λ P2 = 0 (2x + 2y – 3z – 7) + λ(2x + 5y + 3z – 9) = 0, passes through (2, 1, 3) (4 + 2 – 9 – 7) + λ(4 + 5 + 9 – 9) = 0 - 10 + λ9 = 0 ⇒ λ = \(\frac{10}{9}\) Required plane is (2x + 2y – 3z – 7) + λ(2x + 5y + 3z – 9) = 0 18x + 18y -27z – 63 + 20x + 50y + 50z – 90 = 0 38x + 68y + 3z – 153 = 0 |
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