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Find the velocity and acceleration at the end of 2 seconds of the particle moving according to the following rules.s = sqrt t + 1

Answer»

SOLUTION :`s = sqrt t + 1`
ds/DT = 1/2 sqrt t`
`(d^2s)/(d^2s)/dt^2= 1/4t^(3/2)`
`(ds)/dt]_(t=2) =1/2 sqrt2`
`(d^2s)/dt^2]_(t=2)= - 1/4 xx 2 sqrt 2=-1/8 sqrt 2` `THEREFORE` velocity is `1/2 sqrt 2` units/sec and ACCELERATION is `-1/8 sqrt 2 units /sec^2`


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