1.

Find the velocity and acceleration at the end of 2 seconds of the particle moving according to the following rules. s = t^3 - 6t^2 + 15t + 12

Answer»

Solution :`s = t^3 - 6T^2 + 15t + 12`
`ds/dt = 3t^2 - 12t + 15`
`(d^2s)/dt^2 = 6t - 12, ds/dt](t=2) = 3` Now `(ds^2)/dt^2](t=2) = 0`


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