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Find the velocity of centre of mass of the system of two moving particles of mass m and 2m, as shown in the figures (i), (ii) and (iii). |
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Answer» Solution :Referring to the equation `vecv_(cm) = (summ_(1)vecv_(1))/(summ_(1))` we have, (i) `vecv_(cm) =((m)(2vhati) + (2m)(-VHATI))/(m+2m) =VEC0` (ii) `vecv_(cm) =(m(2vhati ) + 2m(vhati))/(m+2m) =(4v)/3 hati` (iii) `vecv_(cm) = (m(2vhati ) + 2m(vhatj))/(m+2m) =(2V)/3(hati + hatj)` |
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