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Find the vertices of the hyperbola `9x^2=16 y^2-36 x+96 y-252=0`A. `(6,3)` and `(-6,3)`B. `(6,3)` and `(-2,3)`C. `(-6,3)` and `(-6,-3)`D. none of these |
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Answer» The equation of the hyperbola is `9(x^(2)-4x+4)-16(y^(2)-6y+9)=144` `implies((x-2)^(2))/(4^(2))-((y-3)^(2))/(3^(2))=1` The coordinates of the vertices are given by `x-2=+-4`, `y-3=0` `impliesx=6`, `y=3` and `x=-2`, `y=3` Hence, the coordinates of the vertices are `(6,3)` and `(-2,3)` . |
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