Find the volume of `Cl_(2)` at `NTP` produced during electrolysis of `MgCl_(2)` which produces `6.6 g Mg`. `("At.wt. of " Mg = 24.3)`

Find the volume of `Cl_(2)` at `NTP` produced during electrolysis of `

1.	Find the volume of `Cl_(2)` at `NTP` produced during electrolysis of `MgCl_(2)` which produces `6.6 g Mg`. `("At.wt. of " Mg = 24.3)`
Answer» Correct Answer - 6 At cathode `Mg^(2+) + 2e rarr Mg` At anode `2Cl^(-) rarr Cl_(2) + 2e` `:.` Equivalent of `Mg` at cathode `=` Equivalent of `Cl_(2)` at anode `:. (6.6)/(24.3//2) = w_(Cl_(2))/35.5" "implies w_(Cl_(2))=19.28 g` Now at NTP `PV=w/m RT` `1xxV=(19.28xx0.0821xx273)/(71)` `implies " "V=6.08` litre `~~6` litre

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Find the volume of `Cl_(2)` at `NTP` produced during electrolysis of `MgCl_(2)` which produces `6.6 g Mg`. `("At.wt. of " Mg = 24.3)`

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