Saved Bookmarks
| 1. |
Find the volume strength of 1.6 N H_(2)O_(2) solution. |
|
Answer» SOLUTION :We know thatstrength =Normality `xx` Eq. wt. and Eq. wt. of `H_(2)O_(2)=17` Strength of 1.6 N `H_(2)O_(2)` solution =`1.6xx17` g/l Now 68 g of `H_(2)O_(2)` GIVES 22400 mL `O_(2)` at N.T.P. `THEREFORE 1.6 xx17g` of `H_(2)O_(2)` will give `(22400)/(68)xx1.6xx17=8960 `mL of `O_(2)` at N.T.P. But `1.6xx17 g` of `H_(2)O_(2)` are present in 1000 mL of`H_(2)O_(2)` solution Hence, 1000 mL of `H_(2)O_(2)` solution gives 8960 mL of `O_(2)` at N.T.P. `therefore ` 1 mL of `H_(2)O_(2)` solution will give `=(8960)/(1000)=8.96` mL of `O_(2)` at N.T.P. Hence, the VOLUME strength of 1.6 `N H_(2)O_(2)` solution =8.96 volume |
|