1.

Find the weight of water supported by surface tension in a capillary tube with a radius of 0.2mm. Surface tension of water is 0.072Nm^(-1) and angle of contact of water is 0^(@)

Answer»

Solution :Assume the weight of WATER to be .F.
weight of water in capillary tube = upward force due to surface tension
i.e., `F=2pir(Scostheta)`
Surface tension of water `S=0.072Nm^(-1)`
ANGLE of contact`theta=0^(@)`
RADIUS of capillary tube `(r)=(0.2)/(1000)m=0.2xx10^(-3)m`
`F=2pir(Scostheta)=2xx(22)/(7)xx0.2xx10^(-3)xx0.072xx1`
`=90.51xx10^(-6)NimpliesF=90.51xx10^(-6)N`


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