1.

Find the weight of water supported by surface tension in a capillary tube with a radius of 0.2 mm. Surface tension of water of 0.072 Nm^(-1) and angle of contact of water is 0^(@).

Answer»

Solution :Assume the weight of water to be F
weight of water in capillary TUBE = upward FORCE DUE to surface tension
i.e. `F=2pir(SCOS theta)`
Surface tension of water `S=0.072Nm^(-1)`
Angle of contact`theta=0^(@)`
Radius of capillary tube `(r)=0.2/1000m=0.2xx10^(-3)m`
`F=2pir(Scos theta)=2xx22/7xx0.2xx10^(-30xx0.072xx1`
`=90.51xx10^(-6)NimpliesF=90.51xx10^(-6)N`


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