Saved Bookmarks
| 1. |
Find the weight of water supported by surface tension in a capillary tube with a radius of 0.2 mm. Surface tension of water of 0.072 Nm^(-1) and angle of contact of water is 0^(@). |
|
Answer» Solution :Assume the weight of water to be F weight of water in capillary TUBE = upward FORCE DUE to surface tension i.e. `F=2pir(SCOS theta)` Surface tension of water `S=0.072Nm^(-1)` Angle of contact`theta=0^(@)` Radius of capillary tube `(r)=0.2/1000m=0.2xx10^(-3)m` `F=2pir(Scos theta)=2xx22/7xx0.2xx10^(-30xx0.072xx1` `=90.51xx10^(-6)NimpliesF=90.51xx10^(-6)N` |
|